Optimal. Leaf size=89 \[ \frac{-2 a c+b^2+b c x^2}{a \left (b^2-4 a c\right ) \sqrt{a+b x^2+c x^4}}-\frac{\tanh ^{-1}\left (\frac{2 a+b x^2}{2 \sqrt{a} \sqrt{a+b x^2+c x^4}}\right )}{2 a^{3/2}} \]
[Out]
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Rubi [A] time = 0.170805, antiderivative size = 89, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 5, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.25 \[ \frac{-2 a c+b^2+b c x^2}{a \left (b^2-4 a c\right ) \sqrt{a+b x^2+c x^4}}-\frac{\tanh ^{-1}\left (\frac{2 a+b x^2}{2 \sqrt{a} \sqrt{a+b x^2+c x^4}}\right )}{2 a^{3/2}} \]
Antiderivative was successfully verified.
[In] Int[1/(x*(a + b*x^2 + c*x^4)^(3/2)),x]
[Out]
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Rubi in Sympy [A] time = 19.3991, size = 78, normalized size = 0.88 \[ \frac{- 2 a c + b^{2} + b c x^{2}}{a \left (- 4 a c + b^{2}\right ) \sqrt{a + b x^{2} + c x^{4}}} - \frac{\operatorname{atanh}{\left (\frac{2 a + b x^{2}}{2 \sqrt{a} \sqrt{a + b x^{2} + c x^{4}}} \right )}}{2 a^{\frac{3}{2}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate(1/x/(c*x**4+b*x**2+a)**(3/2),x)
[Out]
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Mathematica [A] time = 0.274109, size = 100, normalized size = 1.12 \[ \frac{\log \left (x^2\right )-\log \left (2 \sqrt{a} \sqrt{a+x^2 \left (b+c x^2\right )}+2 a+b x^2\right )}{2 a^{3/2}}+\frac{2 a c-b^2-b c x^2}{a \left (4 a c-b^2\right ) \sqrt{a+b x^2+c x^4}} \]
Antiderivative was successfully verified.
[In] Integrate[1/(x*(a + b*x^2 + c*x^4)^(3/2)),x]
[Out]
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Maple [A] time = 0.018, size = 99, normalized size = 1.1 \[{\frac{1}{2\,a}{\frac{1}{\sqrt{c{x}^{4}+b{x}^{2}+a}}}}-{\frac{b \left ( 2\,c{x}^{2}+b \right ) }{2\,a \left ( 4\,ac-{b}^{2} \right ) }{\frac{1}{\sqrt{c{x}^{4}+b{x}^{2}+a}}}}-{\frac{1}{2}\ln \left ({\frac{1}{{x}^{2}} \left ( 2\,a+b{x}^{2}+2\,\sqrt{a}\sqrt{c{x}^{4}+b{x}^{2}+a} \right ) } \right ){a}^{-{\frac{3}{2}}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int(1/x/(c*x^4+b*x^2+a)^(3/2),x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \text{Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/((c*x^4 + b*x^2 + a)^(3/2)*x),x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.317143, size = 1, normalized size = 0.01 \[ \left [\frac{4 \, \sqrt{c x^{4} + b x^{2} + a}{\left (b c x^{2} + b^{2} - 2 \, a c\right )} \sqrt{a} +{\left ({\left (b^{2} c - 4 \, a c^{2}\right )} x^{4} + a b^{2} - 4 \, a^{2} c +{\left (b^{3} - 4 \, a b c\right )} x^{2}\right )} \log \left (\frac{4 \, \sqrt{c x^{4} + b x^{2} + a}{\left (a b x^{2} + 2 \, a^{2}\right )} -{\left ({\left (b^{2} + 4 \, a c\right )} x^{4} + 8 \, a b x^{2} + 8 \, a^{2}\right )} \sqrt{a}}{x^{4}}\right )}{4 \,{\left ({\left (a b^{2} c - 4 \, a^{2} c^{2}\right )} x^{4} + a^{2} b^{2} - 4 \, a^{3} c +{\left (a b^{3} - 4 \, a^{2} b c\right )} x^{2}\right )} \sqrt{a}}, \frac{2 \, \sqrt{c x^{4} + b x^{2} + a}{\left (b c x^{2} + b^{2} - 2 \, a c\right )} \sqrt{-a} -{\left ({\left (b^{2} c - 4 \, a c^{2}\right )} x^{4} + a b^{2} - 4 \, a^{2} c +{\left (b^{3} - 4 \, a b c\right )} x^{2}\right )} \arctan \left (\frac{{\left (b x^{2} + 2 \, a\right )} \sqrt{-a}}{2 \, \sqrt{c x^{4} + b x^{2} + a} a}\right )}{2 \,{\left ({\left (a b^{2} c - 4 \, a^{2} c^{2}\right )} x^{4} + a^{2} b^{2} - 4 \, a^{3} c +{\left (a b^{3} - 4 \, a^{2} b c\right )} x^{2}\right )} \sqrt{-a}}\right ] \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/((c*x^4 + b*x^2 + a)^(3/2)*x),x, algorithm="fricas")
[Out]
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Sympy [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{1}{x \left (a + b x^{2} + c x^{4}\right )^{\frac{3}{2}}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/x/(c*x**4+b*x**2+a)**(3/2),x)
[Out]
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GIAC/XCAS [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{1}{{\left (c x^{4} + b x^{2} + a\right )}^{\frac{3}{2}} x}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/((c*x^4 + b*x^2 + a)^(3/2)*x),x, algorithm="giac")
[Out]